Given:
The system of equation is,
![\begin{gathered} y=-3x+8 \\ 6x+2y=16 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/1ya6jlinvtot7l9tlmaf098bd4d8ndsgiv.png)
Simplify both the equation,
![\begin{gathered} y=-3x+8 \\ 3x+y-8=0\ldots\ldots\ldots\text{.}(1) \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/jy8h1rrra988tfk5s9t379cdrhwopj2b9g.png)
and,
![\begin{gathered} 6x+2y=16 \\ \text{Divide by 2 on both side} \\ (6x)/(2)+(2y)/(2)=(16)/(2) \\ 3x+y=8 \\ 3x+y-8=0\ldots\ldots\ldots.(2) \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/j7nve9gtxvshon2ozcjq49pggvv2l5sun1.png)
It is observed that both the equations of line are same. moreover the lines completely overlap.
It shows the system has infinitely many solutions.
Now check the points (-5,0) ,(7, -13),(1,8),(-2, 14) represents the solution of the given system of equation.
![\begin{gathered} \text{For }(7,-13) \\ \text{Put x=7 in }3x+y-8=0 \\ 3(7)+y-8=0 \\ 21-8+y=0 \\ y=-13 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/m2ghy8mll88dw616sfaz8ofeug7837e7d2.png)
![\begin{gathered} \text{For (-2,14)} \\ \text{Put x=-2 in }3x+y-8=0 \\ 3(-2)+y-8=0 \\ -6-8+y=0 \\ y=14 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/5ceerrbxefn1wcoq6h1581tith0jdpdb50.png)
![\begin{gathered} \text{For (1,8) ,Put x = 1} \\ 3x+y-8=0 \\ 3(1)+y-8=0 \\ y-5=0 \\ y=5 \\ \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/bv4zq9i41idmzod9w0erk7j23w2ha2o04j.png)
This is not the solution of the given system of equations as it does not satisfy the equation.
Also point ( -5,0) is also not the solution of the equation.
Answer:
The system of equation has infinitely many solution and point (7, -13) and (-2, 14) is the solution.