Question

a balloon as a volume of 5 L at a pressure of 0.9 atm. what is the volume of the balloon in liters of the atmospheric pressure is reduced to 0.152 atm

Answer 1

Assuming that the temperature is constant we can use the Boyle's law:

`P_1V_1=P_2V_2`

Solving for V2 and using the data provided in the text:

`V_2=(P_1V_1)/(P_2)=\frac{0.9\text{ atm}\cdot\text{5L}}{0.152atm}=29.6L`