Question

Use your average value for heat of fusion to determine the kJ needed to melt 40.0grams of ice.

Answer 1

To determine the heat needed to melt 40g of ice we use the following formula:

`Q=m.\Delta H_f`

Where:

m is the mass of water

Hf is the heat of fusion

In this case we consider that the process hapens at 0°C.

The average heat of fusion is:

`\Delta H_f=333(J)/(g)`

So we calculate:

`Q=40g.333(J)/(g)=13320J`

Now we convert the value to kJ:

`Q=13320J.(1kJ)/(1000J)=13.32kJ`

So the answer is 13.32kJ.