In this question, we have to determine which compound will present the highest polarization value based on the electronegativity of each element, the values are:
B = 2.04, F = 3.98
3.98 - 2.04 = 1.94
H = 2.2, Cl = 3.16
3.16 - 2.2 = 0.96
Li = 0.98, O = 3.44
3.44 - 0.98 = 2.46
Be = 1.57, Br = 2.96
2.96 - 1.57 = 1.39
Based on this calculations, the compound that has the highest value of polarization is Li-O, letter C is correct