Question

Solve this system using the elimination method. a-3b=4 ; 2a=6b-9

Answer 1

a = k, b = (k-4)/3

Step-by-step explanation:

Given the simultaneous equation;

a-3b=4 ..... 1

2a=6b-9​ .... 2

The equations can also be written as;

a-3b=4 ..... 1 * 2

2a-6b = -9​ ...... 2 * 1

_________________________

2a-6b = 8

2a-6b = -9​

Subtract

-6b + 6b = 8+9

0b = 17

b = 17/0

This shows that a and b has infinite number of solutions;

From equation 1

Let a = k

k - 3b = 4

3b = k-4

b = (k-4)/3

Hence a = k, b = (k-4)/3 where k is any integer