Question

Find the unknown sizes of an angles of the following polygons.​

Answer 1

A is an irregular pentagon - total angle is 540. So x is 100

(540 - 440=100)

B. 3a + 345 = 540

- 345 both sides

3a=195

÷3

a = 65

2a = 130 (65x2)

C. X = 120 (angles on straight lines adds to 180)

3y + 300 = 540

- 300

3y = 240

÷3

Y= 80

x 2

2Y = 160

Hope this helps!