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1)Given the function f(t) =7^2+t-3. Calculate the following valuesg(0)=-3g(2)=27g(-2)=232)In the 2 boxes below, enter your answer as a simplified expression. Do not use any parentheses. Be sure your variables math those in the question.g(t+1)=g(-t)=I'm stock on #2

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Step 1


\begin{gathered} 1)g(t)=7t^2+t-3 \\ find\text{ g(t+1)} \\ g(t+1)=7(t+1)^2+t+1-3 \\ g(t+1)=7(t+1)(t+1)+t+1-3 \\ g(t+1)=7(t^2+t+t+1)+t-2 \end{gathered}
\begin{gathered} g(t+1)=7(t^2+2t+1)+t-2 \\ g(t+1)=7t^2+14t+7+t-2 \\ g(t+1)=7t^2+15t+5 \end{gathered}
\begin{gathered} 2)g(-t)=7(-t)^2+(-t)-3 \\ g(-t)=7t^2-t-3 \end{gathered}

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