Question

If point A is located at (-7 , 5) on a coordinate plane, and point B is located at (4 , 5), what is the distance between the two points?​

Answer 1

`11`

Explanation:

`\sf{Use\: the\: distance\: formula\: to\: determine\: the\: distance\: between\: two\: points.`

`\sf{Distance=√((x_2 - x_1)^2 + (y_2-y_1)^2)`

`\mathrm{Plug\:the\:points}`

`√(\left(4-\left(-7\right)\right)^2+\left(5-5\right)^2)`

`(4+7)^2=11^2\\(5-5)^2=0`

`√(11^2+0)`

`11^2+0=11^2\\√(11^2)`

`\mathrm{Apply\:radical\:rule:\:}\sqrt[n]{a^n}=a,\:\quad \mathrm{\:assuming\:}a\:\mathrm{is\ greater\ than \:or\ equal\: to \:0}`

`=11`