d)
1) Let's begin with that by finding the probability of picking each drink
We need then to find the sample space, the total number of drinks: 14+28+7=49
The probability of picking water is found by:

The probability of picking cola is then:

And the probability of picking Lemonade is:

2) Now, let's analyze the statements:
a) You are twice as likely to select cola than water:
Let's divide these probabilities and check:

True
b)

True
c) We can compare the probabilities in their decimal form:

True
d)

False