Question

In Mr. Lowery's mathematics class, 6/8 of the students received A's and 1/8 received B's. What fraction of the students received either A's or B's?

Answer 1

`(7)/(8)`

Step-by-step explanation

Given:

`\begin{gathered} A=(6)/(8) \\ B=(1)/(8) \end{gathered}`

Fraction of A or B

`\begin{gathered} A+B=(6)/(8)+(1)/(8) \\ take\text{ the LCM} \\ =(6+1)/(8) \\ =(7)/(8) \end{gathered}`

Hence, the fraction of the students received either A's or B's is 7/8.