Given:
The acceleration of the dolphin is
![a=1.77\text{ m/s}^2](https://img.qammunity.org/2023/formulas/physics/college/9mrao0hgyifv7txfl7i78ojcrll07lt3c1.png)
The time taken by the dolphin is
![t=3.33\text{ s}](https://img.qammunity.org/2023/formulas/physics/college/yv76z83e2rtkmshdehzi6jj8ietmk7qeyz.png)
The velocity of the dolphin at the end is
![v=8.77\text{ m/s}](https://img.qammunity.org/2023/formulas/physics/college/dua9u86gwju444ruolsb3nh482oc4pqrds.png)
Required: the displacement of the dolphin
Explanation:
The displacement of the dolphin can be calculated by the third equation of motion. that is given by
![s=ut+(1)/(2)at^2](https://img.qammunity.org/2023/formulas/physics/college/obvwlaq2brhvduordk5kuedw6274qqa7x1.png)
we assume that the initial velocity of the dolphin is zero u=0.
plugging all the values in the above equation, we get
![\begin{gathered} s=0*3.33\text{ s+}(1)/(2)*1.77\text{ m/s}^2*(3.33\text{ s})^2 \\ s=9.81\text{ m} \end{gathered}](https://img.qammunity.org/2023/formulas/physics/college/e2dav813fulxtkg8oq77mtnyqdguqk7srr.png)
Thus, the displacement of the dolphin is
![9.81\text{ m}](https://img.qammunity.org/2023/formulas/physics/college/rlh8g2f4qslp9wgsoe91a3z65briaazta4.png)