Question

Write the equation of the line that passes through (1, 5) and (-2, 14) in slope-intercept formA) y=3x+2B) y=3x+8C) y=-3x-2D) y= -3x+8

Answer 1

Given

The line passes through (1, 5) and (-2, 14).

To write the equation in slope intercept form.

Step-by-step explanation:

It is given that,

The line passes through (1, 5) and (-2, 14).

The slope intercept form of the line is given by,

`y=mx+c`

Since the line passes through (1,5) and (-2,14).

Then, the equation of the line is,

`\begin{gathered} (y-y_1)/(y_2-y_1)=(x-x_1)/(x_2-x_1) \\ (y-5)/(14-5)=(x-1)/(-2-1) \\ (y-5)/(9)=(x-1)/(-3) \\ -3(y-5)=9(x-1) \\ -(y-5)=3(x-1) \\ -y+5=3x-3 \\ -y=3x-3-5 \\ -y=3x-8 \\ y=-3x+8 \end{gathered}`

Hence, the answer is D) y= -3x+8.