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a musician plans to perform five selections for a concert. if he can choose from eight different selections how many ways can I arrange his program

1 Answer

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Answer:

56 ways

Explanations:

Since the exercise involves an arrangement, it is a permutation

The permutation of r objects in n objects is given by the formula


\text{nPr = }(n!)/((n-r)!r!)

The musician is arranging 5 selections in 8

Therefore:


\begin{gathered} 8P5\text{ = }(8!)/((8-5)!5!) \\ 8P5\text{ = }(8!)/(3!5!) \\ 8P5\text{ = }(8*7*6*5!)/(3*2*1*5!) \\ 8P5\text{ = }(8*7*6)/(3*2) \\ 8P5\text{ = 8 }*\text{ 7} \\ 8P5\text{ = }56 \end{gathered}

He can arrange his program in 56 ways

User Michal Rus
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