Given:
Power for coffee maker = 1600 watts
Time indicated for the cofee maker = 10 minutes
Power for microwave = 1100 watts
Time indicated for the microwave = 4 minutes
Cost per hour of electrical appliances = $0.08 kwh
Let's find the total cost to use the appliances.
First convert the power to from watts to kilowatts by dividing by 1000.
![\begin{gathered} P_(coffemaker)=(1600)/(1000)=1.6\text{ kw} \\ \\ P_(microwave)=(1100)/(1000)=1.1\text{ kw} \end{gathered}](https://img.qammunity.org/2023/formulas/physics/college/ghnbkoe7tz3pja93i121ebmnkne69r1lcb.png)
Next step is to convert the time from minutes to hours:
![\begin{gathered} T_(coffeemaker)=(10)/(60)=(1)/(6)\text{hour} \\ \\ T_(microwave)=(4)/(60)=(1)/(15)hour \end{gathered}](https://img.qammunity.org/2023/formulas/physics/college/ja4pyefxclydkyr5nrb5ijrwega7p6fi0i.png)
Thus, to find the total cost to use the appliances, we have:
![\text{Total cost = \lbrack(1.6}\ast(1)/(6))+(1.1\ast(1)/(15))\rbrack\ast0.08](https://img.qammunity.org/2023/formulas/physics/college/fdd4rrtvx9xsuibfhk39ek2oo5u86u493s.png)
Solving further:
![\begin{gathered} \text{Total cost = \lbrack{}0.2}67+0.073\rbrack\ast0.08 \\ \\ \text{Total cost = }(0.340)\ast0.08 \\ \\ \text{Total cost = }0.0272 \end{gathered}](https://img.qammunity.org/2023/formulas/physics/college/ygcv1ugvqm0losbuqvwhuh6ethmxfbwsu8.png)
Therefore, the cost to use the appliances is $0.0272 which is approximately $0.03
ANSWER:
$0.0272