Answer:
Speed of slower bus = 50mph and
speed of faster bus = 60 mph
Step-by-step explanation:
Let speed of first bus be x mph
Then speed of second bus = x+10 mph.
Let A and B have a distance d.
Then given that faster bus reached in 3.5 hours.
i.e. ... i
THe other bus was away from B by 1/6 times d.
Distance travelled by slower bus = 1-1/6 = 5d/6
Time taken = 3.5 hours
i.e. ... ii
Divide i by ii to eliminate d.
ie Speed of slower bus = 50mph and
speed of faster bus = 60 mph
Use ii equation
miles