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What is the y-intercept of the function
y = (x - 1)^(2) + 3

User Crouch
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1 Answer

4 votes

Answer:

(0,4)

Step-by-step explanation:

The y-intercept of a function is the value of y when x=0.

Given the function:


y=(x-1)^2+3

When x=0


\begin{gathered} y=(0-1)^2+3 \\ =(-1)^2+3 \\ =1+3 \\ =4 \end{gathered}

The y-intercept of the function is (0,4).

User Nicu
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