Question

Find the mass of the meter stick (100 cm). For this problem you do not have to convert the grams to kilograms ornewtons.Remember:Only respond with a numerical answer. No units are required.

Answer 1

The center of the stick from the left edge of the stick is at,

`\begin{gathered} d=(100)/(2) \\ d=50\text{ cm} \end{gathered}`

The mass 125 g is at the distance of 25 cm from the hanging.

Thus, the distance of center of the stick from the hanging is,

`\begin{gathered} d^(\prime)=50-25 \\ d^(\prime)=25\text{ cm} \end{gathered}`

As the stick is balanced,

Thus, the net moment due to the mass of the stick and given 125 g mass is zero.

`125* g*25-m* g*25=0`

where g is the acceleration due to gravity,

Substituting the known values,

`\begin{gathered} 125*9.8*25-m*9.8*25=0 \\ (125-m)*9.8*25=0 \\ (125-m)=0 \\ m=125\text{ g} \end{gathered}`

Thus, the mass of the stick is 125 grams.

In the terms of kilogram, the value of the mass is,

`\begin{gathered} m=125*10^(-3)\text{ kg} \\ m=0.125\text{ kg} \end{gathered}`

The value of the mass in newton is,

`\begin{gathered} W=m* g \\ W=0.125*9.8 \\ W=1.225\text{ N} \end{gathered}`

Thus, the value of the weight of the stick is 1.225 N.