Question

Not a timed or graded assignment. Need help. Will give amazing review for a quick answer.

Answer 1

The question requires us to balance the equation for the reaction between Na3PO4 and KOH.

To balance a chemical reaction, we need to find coefficients to achieve the same number of atoms of each element on both sides of the equation.

A simple way to balance an equation is follow the order metals > nonmetals > carbon > hydrogen > oxygen.

Given the information above, we'll proceed to balance the equation given.

`Na_3PO_4+KOH\to NaOH+K_3PO_4`

There are 3 atoms of sodium (Na) on the left side of the equation, thus we can change the coefficient for NaOH from 1 to 3 to have the same amount of Na atoms on the right side:

`Na_3PO_4+KOH\to3NaOH+K_3PO_4`

To balance the amount of potassium (K), another metal, we can change the coefficient of KOH from 1 to 3 to achieve three atoms of K on both sides of the equation:

`Na_3PO_4+3KOH\to3NaOH+K_3PO_4`

Now, let's check the amount of atoms before moving on to balancing hydrogen and oxygen:

Na: 3 atoms on the left side and 3 atoms of the right side

K: 3 atoms on the left side and 3 atoms on the right side

P: 1 atom on the left side and 1 atom on the right side

H: 3 atoms on the left side and 3 atoms on the right side

O: 7 atoms on the left side and 7 atoms on the left side

Therefore, the equation is balanced just by changing the coefficients for KOH and NaOH.

The following coefficients are required to answer the question: 1, 3, 3, 1