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I need help with this It’s from my trigonometry prep guide *it asks to round the answer to the nearest tenth of a degree

I need help with this It’s from my trigonometry prep guide *it asks to round the answer-example-1

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Answer: 50.8

We can answer this question by using the Trigonometric Functions sine and cosine.

To find an angle using the sine function, we know that:


\begin{gathered} \sin \theta=(opposite)/(hypotenuse) \\ \theta=\sin ^(-1)(opposite)/(hypotenuse) \end{gathered}

This will give us:


\theta=\sin ^(-1)\frac{2\sqrt[]{6}}{2\sqrt[]{15}}=39.2\degree

Then, to find the other angle, we can either:

- Add 39.2 and 90, then subtract from 180, or

- Use the trigonometric function cosine.

Let us first try using the function cosine:


\begin{gathered} \cos \theta=(adjacent)/(hypotenuse) \\ \theta=\cos ^(-1)(adjacent)/(hypotenuse) \end{gathered}

This will give us:


\theta=\cos ^(-1)\frac{2\sqrt[]{6}}{2\sqrt[]{15}}=50.8\degree

Then let us try adding 90 and 39.2 then subtract it from 180


180\degree-(90\degree+39.2\degree)=50.8\degree

Now, we have the value of two acute angles which are 39.2 and 50.8. Since we are asked for the larger acute angle, the answer would be 50.8.

I need help with this It’s from my trigonometry prep guide *it asks to round the answer-example-1
User Arntg
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