Answer: 50.8
We can answer this question by using the Trigonometric Functions sine and cosine.
To find an angle using the sine function, we know that:
![\begin{gathered} \sin \theta=(opposite)/(hypotenuse) \\ \theta=\sin ^(-1)(opposite)/(hypotenuse) \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/high-school/wlvlo3mm846slj9fxr8514yixmfl4jcl9q.png)
This will give us:
![\theta=\sin ^(-1)\frac{2\sqrt[]{6}}{2\sqrt[]{15}}=39.2\degree](https://img.qammunity.org/2023/formulas/mathematics/high-school/paaghv7pswv0epidzy77y2nwqyav8ly0lc.png)
Then, to find the other angle, we can either:
- Add 39.2 and 90, then subtract from 180, or
- Use the trigonometric function cosine.
Let us first try using the function cosine:
![\begin{gathered} \cos \theta=(adjacent)/(hypotenuse) \\ \theta=\cos ^(-1)(adjacent)/(hypotenuse) \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/high-school/h7i14vn4w83pcmqc7u3k873r0gbftqim8w.png)
This will give us:
![\theta=\cos ^(-1)\frac{2\sqrt[]{6}}{2\sqrt[]{15}}=50.8\degree](https://img.qammunity.org/2023/formulas/mathematics/high-school/nhmvaw1yo9xufwly2os8n2qsotkqu288zf.png)
Then let us try adding 90 and 39.2 then subtract it from 180
![180\degree-(90\degree+39.2\degree)=50.8\degree](https://img.qammunity.org/2023/formulas/mathematics/high-school/xg5eug7csfe0s8sm3dmboptlxxfeyforr3.png)
Now, we have the value of two acute angles which are 39.2 and 50.8. Since we are asked for the larger acute angle, the answer would be 50.8.