Question

Write the equation of the line that goes through the points (-2, -9) and (3, 1). y=

Answer 1

The slope of the line that passes through the points (x1, y1) and (x2, y2) is computed as follows:

`m=(y_2-y_1)/(x_2-x_1)`

Replacing with the points (-2, -9) and (3, 1),

`y=(1-(-9))/(3-(-2))=(10)/(5)=2`

The slope-intercept form of a line is:

y = mx + b

where m is the slope and b is the y-intercept

Replacing with m = 2 and point (3,1) into the equation, we get:

1 = 2(3) + b

1 = 6 + b

1 - 6 = b

-5 = b

Therefore, the equation is:

y = 2x - 5