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Is 46,386 divisible by both 3 and 9? Why or why not?

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Every number divisible by 9 is divisible by 3. A number is divisible by 9, if the sum is a multiple of 9 or if the sum of its digits is divisible by 9.

In this case:


\begin{gathered} 46,386 \\ 4+6+3+8+6=27 \\ 27\text{ is divisible by 9} \end{gathered}

Then, 46,386 is divisible by 9 and by 3 because every number divisible by 9 is divisible by 3.

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