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Describe the transformation of the graph. f (x) = x3,g(x) = -3(x + 4)3 + 2 O Right 4 units Up 2 Units SES Reflection over the x-axis Vertical stretch by a factor of 3

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\begin{gathered} f(x)\text{ transformed right 4 units becomes } \\ \text{f(x+4)=(x+4)}^{(1)/(3)} \end{gathered}

Let h(x)=f(x+4)

Transformation of h(x) by up 2 units gives a new function say d(x) such that


\begin{gathered} d(x)-2\text{=(x+4)}^{(1)/(3)} \\ d(x)\text{=(x+4)}^{(1)/(3)}+2 \end{gathered}

User Ruben Infante
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