Part a
total outcomes=9
bb yy rr
by br
yb yr
rb ry
Part b
Probability Distribution Table
numbers of yellows
yy by yb yr ry
two yellows ------> 1/9
one yellow and one blue ---->2/9
one yellow and one red ----> 2/9
distribution table
Let
x -----> number of yellows
X------> P(X)
0 ------> 4/9
1 ------> 4/9
2 ------>1/9