SOLUTION:
Step 1 :
In this question, we have that:
The area of the great circle in a sphere is 36 pi square feet.
We are asked to find The surface area of the sphere and
The volume of the sphere.
Step 2:
We have that:
![\begin{gathered} Area\text{ of the circle = 36}\pi \\ \pi r^2\text{ = 36 }\pi\text{ } \\ \text{Divide both sides by }\pi\text{ , we have that:} \\ r^2\text{ = 36} \\ \text{square - root both sides, we have that:} \\ \text{r = 6} \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/ez1n989rdyjxwrvenksfdwn2c57uzdyfqz.png)
Step 3:
Next, we solve for the surface area of the sphere:
![\begin{gathered} \text{Surface Area of the Square= 4 x }\pi Xr^2 \\ \text{Now, we have that r = 6, then we have that:} \\ \text{Surface Area of the square = 4 X}\pi X6^2 \\ =\text{ 4 X }\pi\text{ X 36 } \\ =\text{ 144 }\pi\text{ square f}eet \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/cr6vm0zsr1osqtk9f0rtozazptec9jo531.png)
The surface area of the sphere is :
![144\text{ }\pi\text{ square f}eet.](https://img.qammunity.org/2023/formulas/mathematics/college/gpnq5n5gc8vcikh73yrphyvizkdh3o4q8n.png)
Step 4 :
Now, we have that:
![\begin{gathered} \text{Volume of the sphere = }(4)/(3)\text{ X }\pi Xr^3 \\ =\text{ }(4)/(3)\text{ X }\pi X6^3 \\ =\text{ }(4)/(3)\text{ X }\pi\text{ X 6 X 6 X 6} \\ =\text{ }(4)/(3)\text{ X }\pi\text{ X 216} \\ =\text{ 288 }\pi\text{ cubic f}eet \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/ee60cqdzmf71d41pabvjmmnarfzotva57q.png)
The volume of the sphere is:
![288\text{ }\pi\text{ cubic fe}et](https://img.qammunity.org/2023/formulas/mathematics/college/2f70i32cfmyg7z101gywmnpbks7vgxmmh0.png)