Question

How much heat is necessary to heat 200 g of water at 10°C to 85°C?

Answer 1

Given

Mass of water, m= 200g

Change in temperature,

`T=85^oC-10^oC=75^oC`

To find

Heat required

Step-by-step explanation

We know specific heat of water is

`c=(4.18J)/(g^oC)`

Thus heat required is

`\begin{gathered} Q=mcT \\ \Rightarrow Q=200*4.18*75 \\ \Rightarrow Q=62700J \end{gathered}`

Conclusion

The heat necessary is 62700 J