According to the explanation given in our previous session
8. N2 + 3 H2 -> 2 NH3
Reactants
N = 2
H = 6
Products
N = 2
H = 6
As we can see, both sides now have the same number of elements, 2 Nitrogens and 6 Hydrogens, this is what we need to do in a balancing reaction question
9. MgCl2 + 2 NaBr -> MgBr2 + 2 NaCl
Reactants
Mg = 1
Cl = 2
Na = 2
Br = 2
Products
Mg = 1
Cl = 2
Na = 2
Br = 2
Same number of elements on both sides