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Suppose a binomial trial has a probability of success of 0.1, and 500 trials areperformed. What is the standard deviation of the possible outcomes? Roundyour answer to two decimal places.A. 10.95B. 10.25C. 8.94D. 6.71

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Standard deviation= √n p q

Where:

n= number of trials (500)

p= probability (0.1)

q= 1-p = 1-0.1 = 0.9

Replacing:

Standard deviation= √[500 (0.1) (0.9)] = √45 = 6.71

D.6.71

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