Question

I like to know the steps to this type of question please and thank you

Answer 1

In this problem they are telling you that the mean is 64 ounces and that the standar derivation is 2.4 onces so:

To find the maximun value that can have Mu we have tu sum the standart derivation to the mean so:

`\text{maximun}=64+2.4=66.4`

and to calculate the minumun value that can have mu we rest the standar derivation from the mean so:

`\text{minumun}=64-2.4=61.6`

so the solution is:

`61.6<\mu<66.4`