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Find the first term and the difference in an arithmetic sequence if the 100th term is 13 and the 200th term is 82. d = ______(simplify the answer using an integer or simplified fraction)

User Raspayu
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1 Answer

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We will have the following:

*First: We know that arithmetic sequences follow:


a_n=a_1+d(n-1)

*Second: From the information given we will have:

a100:


13=a_1+d(100-1)\Rightarrow13=a_1+99d

a200:


82=a_1+d(200-1)\Rightarrow82=a_1+199d

Then we will find the common difference:


d=(82-13)/(200-100)\Rightarrow d=(69)/(100)\Rightarrow d=0.69

So, the common difference is 0.69.

*Third: We determine the first term:


13=a_1+0.69(99)\Rightarrow_{}13=a_1+68.31
\Rightarrow a_1=-55.31\Rightarrow a_1=-(5531)/(100)

So, the first term is -55.31.

User Tom Kris
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