Question

In ΔNOP, the measure of ∠P=90°, NO = 88 feet, and PN = 62 feet. Find the measure of ∠O to the nearest degree

Answer 1

By definition:

`\sin (angle)=\frac{\text{opposite side}}{hypotenuse}`

From the picture:

`\begin{gathered} \sin (x)=(62)/(88) \\ x=\arcsin ((62)/(88)) \\ x\approx45\text{ \degree} \end{gathered}`