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Hello, I need some help with Part 2 question 5! Please show work as the instructions asked! I included other completed work from the assignment for extra information.

Hello, I need some help with Part 2 question 5! Please show work as the instructions-example-1
Hello, I need some help with Part 2 question 5! Please show work as the instructions-example-1
Hello, I need some help with Part 2 question 5! Please show work as the instructions-example-2
Hello, I need some help with Part 2 question 5! Please show work as the instructions-example-3
User Mirac
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1 Answer

6 votes

SOLUTION

The given polynomial is:


(x+7)(x-2)^2(x^2-4)(x+1)^4

Using differece of squares, it follows:


\begin{gathered} (x^2-4) \\ =\lparen x^2-2^2) \\ =(x-2)(x+2) \end{gathered}

Substituting the expression into the given polynomial gives:


(x+7)(x-2)^2(x-2)(x+2)(x+1)^4

Thus the polynomial becomes:


(x+7)(x-2)^3(x+2)(x+1)^4

Using the Fundamental Theorem of Algebra the number of roots of the polynomial is equal to the degree of the polynomial.

Thus the number of roots is:


1+3+1+4=9

Therefore the number of roots is 9.

Notice that the factor with multiplicity of 3 is (x-2)

Therefore the code piece is E

User Penanghill
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