Given:
The force of attraction is F = 10 N.
Let the mass of each ball is m and the distance between them is r.
To find:
The force of attraction when one of the balls has a mass of 2m and the distance between them is 3r.
Solution:
The force of attraction is given by the formula

Here, G is the gravitational constant.
The new force of attraction will be

Final Answer: The force of attraction when the mass of one of the balls doubled and the distance between them is tripled will be 2.22 N.