The given area of the square is:

The area of a square is given by the formula:

If we replace the given value we obtain:

The result of this square root is not an integer, and the closest square roots that are exact numbers are:

As the rational numbers need to be within 1/8 inch of the actual side length, it is:

As the square root of 150 is between 12 and 13, we can use any two whole numbers that are less than 13 and divide by 8 to obtain a number less than sqrt(150)/8, for example, 12:

Now, another number could be 10, so:

Two rational numbers that are within 1/8 inch of the actual side length could be: 3/2 and 5/4