Question

Solve the system of equations. x=2y-5 -3x=-6y+15

Answer 1

We have the system of equations:

`\mleft\{\begin{aligned}x=2y-5\text{ (equation 1)} \\ -3x=-6y+15\text{ (equation 2)}\end{aligned}\mright.`

Notice that in (equation 1) the variable x is already clear. Let's substitute in (equation 2), so we can find the value of y:

`\begin{gathered} -3x=-6y+15 \\ \rightarrow-3(2y-5)=-6y+15 \\ \rightarrow-6y+15=-6y+15 \end{gathered}`

Notice that this is true for any value of y

Thereby, the system has infinite solutions