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Give the sin, cos, and tan for the point on the Unit Circle at 210°

Give the sin, cos, and tan for the point on the Unit Circle at 210°-example-1

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It's important to know that the unit circle refers to a circle with a radius of 1 unit. As the image below shows.

As you can observe, in the graph, the angle 210° is placed on the third quadrant, where cosine and sine functions are negative tangent functions are positive.


\begin{gathered} y=\cos (210)=-\cos 30=-\frac{\sqrt[]{3}}{2} \\ y=\sin (210)=-\sin 30=-(1)/(2) \end{gathered}

Then, we divide the functions above to find the tangent


\tan (210)=(\sin(210))/(\cos(210))=\frac{-(1)/(2)}{-\frac{\sqrt[]{3}}{2}}=\frac{1}{\sqrt[]{3}}\cdot\frac{\sqrt[]{3}}{\sqrt[]{3}}=\frac{\sqrt[]{3}}{3}

Hence, the functions are


\begin{gathered} \sin (210)=-(1)/(2) \\ \cos (210)=-\frac{\sqrt[]{3}}{2} \\ \tan (210)=\frac{\sqrt[]{3}}{3} \end{gathered}

Give the sin, cos, and tan for the point on the Unit Circle at 210°-example-1
User Ummahusla
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