It's important to know that the unit circle refers to a circle with a radius of 1 unit. As the image below shows.
As you can observe, in the graph, the angle 210° is placed on the third quadrant, where cosine and sine functions are negative tangent functions are positive.
![\begin{gathered} y=\cos (210)=-\cos 30=-\frac{\sqrt[]{3}}{2} \\ y=\sin (210)=-\sin 30=-(1)/(2) \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/r8dd23s3o73eky3n7o8sds1tipju3vtq26.png)
Then, we divide the functions above to find the tangent
![\tan (210)=(\sin(210))/(\cos(210))=\frac{-(1)/(2)}{-\frac{\sqrt[]{3}}{2}}=\frac{1}{\sqrt[]{3}}\cdot\frac{\sqrt[]{3}}{\sqrt[]{3}}=\frac{\sqrt[]{3}}{3}](https://img.qammunity.org/2023/formulas/mathematics/college/43hqdayie8bmoh56lwefp1ku0zvd0ioja6.png)
Hence, the functions are
![\begin{gathered} \sin (210)=-(1)/(2) \\ \cos (210)=-\frac{\sqrt[]{3}}{2} \\ \tan (210)=\frac{\sqrt[]{3}}{3} \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/5xhgis5jqriikngctqffpa2lnwlqkzv1sp.png)