Question

The Specific Heat of lead is 0.13 J/g°C. How much heat (in J) is required to increase the temperature of 15 g of lead from 22 °C to 37 °C? A. -0.13 B. 2.0 C. 0.13 D. 29

Answer 1

D. 29

Step-by-step explanation

Given:

mass of lead (m) = 15 g

heat (Q) = ?

Specific heat of lead (Cp) = 0.13 J/g°C

Initial temperature = 22 °C

Final temperature = 37 °C

Required: Heat required to increase the temperature.

Solution

To solve this problem, use the following formula:

Q = m x Cp x ΔT where Q is the heat, Cp is the specific heat, m is the mass and Δ T is the change in temperature

Q = 15 g c x 0.13 J/g°C x (37-22°C)

Q = 29.25 J