Question:
Solution:
Consider the following function:
![h(x)=-3(x-3)^2+108](https://img.qammunity.org/2023/formulas/mathematics/college/aqeanmx8jckjkmlkpnuht8h0nwjahvcdgr.png)
where x is measure in seconds and h(x) represents the height of the object. Now, if the hovercraft land on the ground then h(x) = 0. Thus, we get:
![0=-3(x-3)^2+108](https://img.qammunity.org/2023/formulas/mathematics/college/a3t5bn4sx8wfvekpm94ipq34h0dmatyt71.png)
Our goal is to solve this for x. Expanding the square we have that the above equation is equivalent to:
![0=-3(x^2-6x+9)^{}+108](https://img.qammunity.org/2023/formulas/mathematics/college/8xj6cm8fpttupy9q2f79bmx859959mvdwh.png)
applying the distributive property we obtain:
![0=-3x^2+18x-27^{}+108](https://img.qammunity.org/2023/formulas/mathematics/college/wkez3xe2t8erk3rxsa2zed28tzrrxhju0m.png)
this is equivalent to:
![0=-3x^2+18x+81](https://img.qammunity.org/2023/formulas/mathematics/college/wcj2igc5rced5ixba1tpi7tiwjtvmg4zyc.png)
or
![-3x^2+18x+81\text{ = 0}](https://img.qammunity.org/2023/formulas/mathematics/college/wrwewoxmb2m9lomrgq7p2811s80fe71yup.png)
Using the quadratic formula we obtain that the solutions of this equation are:
![x\text{ = -3 and }x=\text{ 9}](https://img.qammunity.org/2023/formulas/mathematics/college/i860yaqihldk2luoxedxd3w900tl3eb5k9.png)
Note that by convention time is positive, therefore the correct answer is
![x\text{ = 9 }](https://img.qammunity.org/2023/formulas/mathematics/college/qqvvwdood6z4vbtwuy903x81ili7mxgvha.png)