151k views
4 votes
At bob bakery he sells three type of cookies to his customers chocolate chip,sugar, and peanut butter in the past hour. Bob sold 5 times as many chocolate chips cookies as peanut butter. Bob sold 7 fewer sugar cookies than chocolate cookiesBob sold 9 peanut butter How many chocolate chip he sold How many sugar cookies he sold How many peanut butter he sold

User MrSnoozles
by
8.7k points

1 Answer

2 votes

45 Chips chocolates cookies

38 sugar cookies

9 peanut butter cookies

Step-by-step explanation

Step 1

make the equations:

let

x represents the number of chocolate chips cookies he sold

y represents the number of sugar cookies he sold

z represents the number of peanut butter cookies he sold

hence, let's traslate

a)Bob sold 5 times as many chocolate chips cookies as peanut butter


x=5z\Rightarrow equation(1)

b)Bob sold 7 fewer sugar cookies than chocolate cookies


y=x-7\Rightarrow equation(2)

c)Bob sold 9 peanut butter


z=9\Rightarrow equation(3)

Step 2

solve the equations

a) replace the z value from equation (3)


\begin{gathered} x=5z\Rightarrow equation(1) \\ x=5(9) \\ x=45 \end{gathered}

therefore, he sold 45 chips chocolate cookies

b)now, replace the x value into equation (2) to find y


\begin{gathered} y=x-7\Rightarrow equation(2) \\ y=45-7 \\ y=38 \end{gathered}

it means he sold 38 sugar cookes

I hope this helps you

User SpankMe
by
8.1k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories