Question

If 6.95 mol of ethane (C2H6) undergo combustion according to the unbalanced equation C2H6 + O2 ——- CO2 + H2OHow many moles of O2 is required? Answer in units of mol.

Answer 1

24.325 mol

Step-by-step explanation

The unbalanced equation is:

C₂H₆ + O₂ → CO₂ + H₂O

The balanced equation will be:

2C₂H₆ + 7O₂ → 4CO₂ + 6H₂O

Given mole of ethane = 6.95 mol

From the balanced equation:

2 mol of C₂H₆ is required by 7 mol of O₂

Therefore, 6.95 mol of C₂H₆wills requir:

`\frac{6.95\text{ mol }C_2H_6*7\text{ mol }O_(2)}{2\text{ mol }C_2H_6}=24.325\text{ mol of }O_(2)`

Hence, 24.325 mol of O2 is required.