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Find the term that must be added to the equation x^2-8=9 to make it into a perfect square

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For this question, we recall that a perfect square is of the form:


(a+b)^(2)

Therefore, we will add and subtract constants in order to arrive at the perfect square form:


\begin{gathered} 9=x^(2)-8x \\ 9=x^(2)-8x+16-16 \\ 9+16=x^(2)-8x+16 \\ 25=(x-4)^(2) \end{gathered}

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