Question

You randomly draw twice from this deck of cards9, 2, 4, 7, 8, 2,1What is the probability of not drawing a 1, then not drawing a 1,without replacing the first card? Write your answer as a percent rounded to the nearest whole number.

Answer 1

Given:

You randomly draw twice from this deck of cards

9, 2, 4, 7, 8, 2, 1

the number of cards = 7

We will find the probability of not drawing a1 then not drawing a1 without replacing the first card.

So, the probability of not drawing a1 first time = 6/7

The probability of not drawing a1 second time:

The number of cards = 7 - 1 = 6

So, the probability = 5/6

So, the total probability =

`(6)/(7)\cdot(5)/(6)=0.714=71.4\%`

Rounding to the nearest whole number

So, the answer will be 71%