The diagonal of a square is 25ft. Find the length of ONE side of the square
we have that
Applying the Pythagorean Theorem
Let
c ----> the diagonal of the square
a----> the length of one side
so
c^2=a^2+a^2
c^2=2a^2
substitute the given values
25^2=2a^2
625=2a^2
a^2=312.5
a=17.68 units
or
exact value is
![\begin{gathered} a=\sqrt[\square]{(625)/(2)} \\ a=\frac{25}{\sqrt[]{2}} \\ a=\frac{25\sqrt[]{2}}{2}\text{ ft} \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/acb4b3wz6rjwng8miic2vr2tfso9w7y7oh.png)