Question

In each part calculate the kinetic energy of the given objects in joules c) an electron (mass 9.11x10^-31kg) moving at a speed of 2.74x10^7m/s

Answer 1

The kinetic energy of an object with mass m that moves with speed v is given by:

`K=(1)/(2)mv^2`

Plugging the mass and speed given in the equation above we have that:

`\begin{gathered} K=(1)/(2)(9.11*10^(31))(2.74*10^7)^2 \\ K=3.42*10^(-16) \end{gathered}`

Therefore, the kinetic energy of the electron is:

`3.42*10^(-16)\text{ J}`