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If np >= 5 and nq >= 5 , estimate P(at least 10) with n = 13 and p = 0.5 by using the normal distribution as an approximation to the binomial distribution ; if np < 5 or nq < 5 then state that the normal approximation is not suitable.

If np >= 5 and nq >= 5 , estimate P(at least 10) with n = 13 and p = 0.5 by-example-1

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The question provides that:


\begin{gathered} n=13 \\ p=0.5 \end{gathered}

Therefore, we have that:


q=1-p=1-0.5=0.5

To check if we can use the normal distribution as an approximation, we will check the values of np and nq:


\begin{gathered} np=13*0.5=6.5 \\ nq=13*0.5=6.5 \end{gathered}

Since,


\begin{gathered} np\ge5 \\ \text{and} \\ nq\ge5 \end{gathered}

then we can use the normal distribution as an approximation.

To evaluate P (at least 10), we are evaluating:


P(X\ge10)

The standard deviation of the distribution is gotten to be:


\sigma=\sqrt[]{np}=\sqrt[]{6.5}=2.550

The mean is 6.5.

Therefore, the Z-score is gotten to be:


Z=\frac{x-\bar{x}}{\sigma}

Hence, it is calculated to be:


Z=(10-6.5)/(2.550)=1.37

The probability is therefore given to be:


P(Z\ge1.37)=Pr(0\le Z)-Pr(0\le Z\le1.37)

Using the Probability Distribution Table, we have:


P(Z\ge1.37)=0.5-0.4147=0.0853\approx0.085

Therefore, the answer is:


P(at\text{ }least\text{ }10)=0.085

User Wagner Silveira
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