Question

`y = 7(x + 5)^(2) + 4`identify the vertex and the axis of symmetry for the following parabola

Answer 1

Could you send me the parabola function?

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Parabola

f(x) = 7 (x +5)^2 +4

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The vertex parabola function is

f(x) = a (x – h) ^2 + k

The vertex is (h, k)

f(x) = 7 (x +5)^2 +4

So then, the vertex is h = -5 and k=