Question

What is the equation of the line that is parallel to the given line and passes through the point (–2, 2)?

y = One-fifthx + 4
y = One-fifthx + Twelve-fifths
y = –5x + 4
y = –5x + Twelve-fifths

Answer 1

B. y = 1/5x + 12/5

Answer 2

y = 1/5x + 12/5

Explanation:

First find the slope of the given line

m = ( y2-y1)/(x2-x1)

m =( -3- -4)/(0- -5)

(-3+4) /(0+5)

1/5

Parallel lines have the same slope

Using point slope form of a line

y-y1 = m(x-x1)

y - 2 = 1/5(x--2)

y -2 = 1/5(x+2)

Distribute

y-2 = 1/5x +2/5

Add 2 to each side

y-2+2 = 1/5x + 2/5 + 2

y = 1/5x + 2/5 + 10/5

y = 1/5x + 12/5