Question

What is the equation of the line that passes through the point (5,0) and has a slope of 11?

Answer 1

y = 11x - 55

Step-by-step explanation:

The equation of the line that passes through the point (x1, y1) and has a slope of m is equal to:

`y-y_1=m(x-x_1)`

Then, we can replace (x1, y1) by (5, 0) and m by 11, to get:

`y-0=11(x-5)`

So, solving for y, we get:

`\begin{gathered} y=11(x)-11(5) \\ y=11x-55 \end{gathered}`

Therefore, the answer is y = 11x - 55