Question

Use the order of operations to evaluate the expression1-5(3 – 4) +3642Ο Α. 19OB 203<Ос. 24D. 33

Answer 1

Given expression is

`4*((3)/(4)-(1)/(2))+3*6`

Recall that the order of operations is

1. Paratheses

2. Exponents.

3. Multiplication.

4. Division.

5. Addition.

6. Subtraction.

First, we need to solve inside the paratheses.

LCM of 4 and 2 is 4, making the denominator 4, we get

`4*((3)/(4)-(1)/(2))+3*6=4*((3)/(4)-(1*2)/(2*2))+3*6`

`=4*((3)/(4)-(2)/(4))+3*6`

`=4*((3-2)/(4))+3*6`

`=4*(1)/(4)+3*6`

Second, we need to solve multiplication.

Multiply 3 and 6, we get

`=4*(1)/(4)+18`

Multiply 4 and 1, we get

`=(4)/(4)+18`

Third, we need to solve division.

Divide 4 into 4, we get

`=1+18`

Fourth, we need to solve addition.

Add 1 and 18, we get

`=19`

Hence the answer is 19.

Option A is correct.