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Consider the two equations below: Equation A: 4x - 2y = -6 Equation B: 3x + y = 3 Rewrite both equations in slope-intercept form to graph both equations on the graph below. Graph Equation A in green and Equation B in blue.

User Karthiks
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1 Answer

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The equation of a line in slope-intercept form looks like this:

y=mx+b

Where m is the slope and b is the intercept of the line with the y-axis.

We can rewrite our equation to make them look like the expression above like this:

Equation A

4x - 2y = -6

4x - 4x - 2y = -6 - 4x

-2y = -6 - 4x

-2y/-2 = (-6-4x)/-2

y = 3 + 2x, this is how equation A look like in slope-intercept form.

Equation B

3x + y = 3

3x - 3x +y = 3 - 3x

y = 3 - 3x, this is how equation B look like in slope-intercept form.

To graph these lines, we just have to find two points of them ( a pair of points for each line), then join them, we can find points of the line by replacing values of x and calculating its corresponding value of y.

Let's take for example x=0

Equation A

y = 3+2*0=3, then we have the point (0,3)

Equation B

y=3-3*0=-3, then we have the point (0,3) (like in equation A)

Now let's take x=1

Equation A

y=3+1*3=3+3=6, then here we have another point (2,6)

Equation B

y=3-3*1=3-3= 0, (2,0)

Now that we now two points of the line described by equation A (0,3) and (2,6) and two points for the equation B (0,3) and (2,0), let's plot them, like this:

Consider the two equations below: Equation A: 4x - 2y = -6 Equation B: 3x + y = 3 Rewrite-example-1
User Robert Monfera
by
6.2k points
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