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Solve the following system of2x + 6y = 14x – 6y= -20

User Mmlac
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We are given the following system of equations:


\begin{gathered} 2x+6y=14,(1) \\ x-6y=-20,(2) \end{gathered}

To solve the system we will use the method of elimination. We will add equations (1) and (2) so that the variable "y" gets canceled out, like this:


2x+6y+x-6y=14-20

Adding like terms:


3x=-6

Now, we divide both sides by 3:


x=-(6)/(3)=-2

Therefore, the value of "x" is -2. Now, we determine the value of "y" by substituting the value if "x" in equation (1):


-2-6y=-20

Now, we add 2 to both sides:


\begin{gathered} -6y=-20+2 \\ -6y=18 \end{gathered}

Now, we divide both sides by -6:


y=(18)/(-6)=-3

Therefore, the solution of the system is:


\begin{gathered} x=-2 \\ y=-3 \end{gathered}

User Thibault Seisel
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